Diagnostic Testing
Hi again and welcome back to my blog,
It has come time to begin diagnostic testing my project and evaluation its efficiency. To start I am testing out how much energy is consumed per opening of the RFID solenoid lock. To do this I connected a multi-meter in series (ammeter) and one in parallel (voltage), by multiplying these two values I can determine the power then multiply that by the time the solenoid is open for (4 secs or delay(400)) and that gives me the total energy (joules).
By calculating that the system draws a current of 0.5848 ohms and 3.384 Volts. The energy used is a total of 7.9159 Joules per opening. I have 3x 18650 cells with each having 2.5 Amp hours and 3.7 Volts each so a total of 9.25 Watt Hours to get that to seconds we multiply it by 3,600 we determine the joules to be 33,300 for each cell (a total of 99,900 Joules for the 3 cells). Now if we divide 99,900 joules total energy by the amount of joules used each turn (7.9159J) we can find how many times it can be used before needing to recharge/ change batteries, approximately the system can open 12,620 openings.
Sorry for the lengthy equations but I hope this helps people understand the efficiency of my project more :)
Thanks for reading,
Perry
P.S.
Below I have attached the image to help people visual it :)
It has come time to begin diagnostic testing my project and evaluation its efficiency. To start I am testing out how much energy is consumed per opening of the RFID solenoid lock. To do this I connected a multi-meter in series (ammeter) and one in parallel (voltage), by multiplying these two values I can determine the power then multiply that by the time the solenoid is open for (4 secs or delay(400)) and that gives me the total energy (joules).
By calculating that the system draws a current of 0.5848 ohms and 3.384 Volts. The energy used is a total of 7.9159 Joules per opening. I have 3x 18650 cells with each having 2.5 Amp hours and 3.7 Volts each so a total of 9.25 Watt Hours to get that to seconds we multiply it by 3,600 we determine the joules to be 33,300 for each cell (a total of 99,900 Joules for the 3 cells). Now if we divide 99,900 joules total energy by the amount of joules used each turn (7.9159J) we can find how many times it can be used before needing to recharge/ change batteries, approximately the system can open 12,620 openings.
Sorry for the lengthy equations but I hope this helps people understand the efficiency of my project more :)
Thanks for reading,
Perry
P.S.
Below I have attached the image to help people visual it :)
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